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3. Instruction Set
3-457
6. Substitute the above parameters into y = kx + b and the operation instruction can be obtained.
y = kx + b = D = k S
1
+ b = slope × S
1
+ offset = slope × S
1
+ min. destination value – min.
source value × slope = slope × (S
1
– min. source value) + min. destination value = (S
1
– min.
source value) × (max. destination value – min. destination value) ÷ (max. source value – min.
source value) + min. destination value
7. If S
1
> max. source value, S
1
will be set as max. source value. If S
1
< min. source value, S
1
will
be set as min. source value. When the source value and parameters are set, the following
output figure can be obtained:
D
1
Min. destination value
Max. Destination value
Destination value
Source value
Max.
source value
Min.
source value
Program Example 1:
1. Assume source value S
1
= 500, max. source value D0 = 3000, min. source value D1 = 200,
max. destination value D2 = 500, and min. destination value D3 = 30. When X0 = ON, SCLP
instruction executes and the result of proportional calculation will be stored in D10.
2. Equation: D10 = [(500 – 200) × (500 – 30)] ÷ (3000 – 200) + 30 = 80.35. Rounding off the
result into an integer, D10 =80.
X0
SCLP
K500
D0
D10
X0
MOV
MOV
MOV
MOV
K3000
K200
K500
K30
D0
D1
D2
D3