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3. Instruction Set
3-455
Program Example 1:
1. Assume S
1
= 500, S
2
= 168 and S
3
= -4. When X0 = ON, SCAL instruction executes and the
result of proportional calculation will be stored in D0.
2. Equation: D0 = (500 × 168 ) ÷ 1000 + (-4) = 80
X0
SCAL
K500
K168 K-4 D0
D
1
0
= 500
Slope=168
Offset=-4
Destination value
Source value
Program Example 2:
1. Assume S
1
= 500, S
2
= -168 and S
3
= 534. When X0 = ON, SCAL instruction executes and the
result of proportional calculation will be stored in D10..
2. Equation: D10 = (500 × -168 ) ÷ 1000+ 534 = 450
X10
SCAL
K500
K-168 K534 D10
Offset = 534
D
S= 500
1
0
Slope = -168
Destination value
Source value
Points to note:
1. This instruction is applicable for known slope and offset. If slope and offset are unknown,
please use SCLP instruction for the calculation.
2. S
2
has to be within the range -32,768 ~ 32,767. If S
2
exceeds the applicable range, use SCLP
instruction instead.
3. When adopting the slope equation, the max source value must be larger than min source
value, but the max destination value does not need to be larger than min destination value.
4. If D > 32,767, D will be set as 32,767. If D < -32,768, D will be set as -32,768.